Chinese National Youth Chess Team Championship 2025(B16) Zadnja izmjena27.08.2025 12:08:04, Creator/Last Upload: Chinesechessassociation
Odabir turnira | G10, G12, G14 B10, B12, B14, B16 |
Linkovi | Livegames, Link tournament to the tournament calendar |
Odabir parametara | pokaži podatke o turniru, Link tournament to the tournament calendar |
Liste | Poredak sa partijama (MP), Poredak sa partijama (Bod.), Poredak, Lista po nositeljstvu, Abecedni popis igrača, Alphabetical list all groups, Satnica, Podaci o Savezima, Partijama i Titulama |
| Turnirski sastav sa rezultatima po kolima, Turnirski sastav bez rezultata po kolima, Parovi ekipa za sva kola |
Bodovi po pločama | Kolo.1, Kolo.2, Kolo.3, Kolo.4, Kolo.5, Kolo.6, Kolo.7, Kolo.8, Kolo.9, Kolo.10, Kolo.11 |
Partije | Postoji 105 partija dostupnih za download |
Pretvori u Excel i Printaj | Pretvoti u Excel (.xlsx), Pretvori u PDF-File, QR-Codes |
Poredak sa partijama (Bod.)
Mj. | Momčad | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | TB1 | TB2 | TB3 | TB4 |
1 | Jiangsu Chengyi | * | | | 2½ | 2 | 2½ | | 3 | 2 | | 2½ | 12 | 14,5 | 0 | 72,5 |
2 | Hangzhou Chess Association | | * | 2½ | 2 | 2 | 2 | | 2 | | 2½ | | 12 | 13 | 0 | 79,5 |
3 | Shanghai Qiyu | | ½ | * | 1½ | | | 2 | 2 | | 3 | 2½ | 9 | 11,5 | 0 | 46,5 |
4 | Qingdao Wanyun | ½ | 1 | 1½ | * | | | 1½ | | 2 | 2½ | 2 | 8 | 11 | 0 | 52 |
5 | Zhejiang | 1 | 1 | | | * | 2 | 2 | | 1½ | | 2½ | 7 | 10 | 0 | 53 |
6 | Shenzhen Zhiqu | ½ | 1 | | | 1 | * | 2 | | 2 | 1 | 2 | 6 | 9,5 | 0 | 45 |
7 | Shenzhen Aoti | | | 1 | 1½ | 1 | 1 | * | 0 | 3 | 2 | | 5 | 9,5 | 0 | 47 |
8 | Qingdao Qingwei | 0 | 1 | 1 | | | | 3 | * | | 2 | 1½ | 5 | 8,5 | 0 | 41,5 |
9 | Shenzhen Xincheng | 1 | | | 1 | 1½ | 1 | 0 | | * | | 2 | 3 | 6,5 | 0 | 38,5 |
10 | Tianjin Yicheng | | ½ | 0 | ½ | | 2 | 1 | 1 | | * | | 2 | 5 | 0 | 32 |
11 | Nanjing Juzhongmi | ½ | | ½ | 1 | ½ | 1 | | 1½ | 1 | | * | 1 | 6 | 0 | 38,5 |
Bilješka: Tie Break1: Matchpoints (2 for wins, 1 for Draws, 0 for Losses) Tie Break2: points (game-points) Tie Break3: The results of the teams in then same point group according to Matchpoints Tie Break4: Sonneborn-Berger-Tie-Break (analog [57] but with all results)
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